Capacitance:

$\overline{){\mathit{C}}{\mathbf{=}}\frac{{\mathit{\epsilon}}_{\mathbf{0}}\mathit{A}}{\mathit{d}}}$

Potential difference:

$\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{Q}}{\mathbf{C}}}$

Electric field:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{d}}}$

**a****)**

Capacitance,

$\mathit{C}\mathbf{=}\frac{\mathbf{(}\mathbf{8}\mathbf{.}\mathbf{85}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{12}}\mathbf{)}{\mathbf{(}\mathbf{2}\mathbf{.}\mathbf{50}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{)}}^{\mathbf{2}}}{\mathbf{3}\mathbf{.}\mathbf{0}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}}$

Two 2.50 cm × 2.50 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC.

a) What is the potential difference across the capacitor if the spacing between the plates is 3.00 mm?

b) What is the electric field strength inside the capacitor if the spacing between the plates is 3.00 mm?

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What scientific concept do you need to know in order to solve this problem?

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